sep-2-17_00
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@@ -13,3 +13,10 @@ AuB = {1, 2, 3, 5, 7, 9}
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A↓uB = {3, 7}
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A\B = {1, 9}
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A"delt"B = {1, 2, 5, 9}
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Beviska:
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1) ¨A↓u(AuB) = B\A
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2) (AuB)↓u¨(A↓uB) = (A↓u¨B)u(B↓u¨A)
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