sep-2-14_54

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2025-09-03 14:54:51 +02:00
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- Mängdoperation:
- Differens: $A\setminus\text{B} = \{x\in\mathcal{U}:x\in\text{A}\land\text{x}\not\in\text{B}\}$
- Symetrisk Differens $A\triangle\text{B}=\{x\in\mathcal{U}:x\in\text{A}\cup\text{B}\land\text{x}\not\in\text{A}\cap\text{B}\}$
- Räkne regler:
- Dublekomplement: $\overline{\overline{A}} = A$
- Idempotens: $A\cup\text{A}=A$, $A\cap\text{A}=A$
- Identitet: $A\cup\emptyset=A$, $A\cap\emptyset=\emptyset$
- Dominans: $A\cup\mathcal{U}=\mathcal{U}$, $A\cap\emptyset=\emptyset$
- Kommutativ: $A\cup\text{B}\iff\text{B}\cup\text{A}$, $A\cap\text{B}\iff\text{B}\cap\text{A}$
- Associativ: $$
\begin{align}
(A\cup\text{B})\cup\text{C}\iff\text{A}\cup(B\cup\text{C})\iff\text{A}\cup\text{B}\cup\text{C} \\ (A\cap\text{B})\cap\text{C}\iff\text{A}\cap(B\cup\text{C})\iff\text{A}\cap\text{B}\cap\text{C}
\end{align}
$$
- Paranteser: om alla oprationer är $\cup$ eller $\cap$ spelar årdning ingen roll
- De Morgand: $\overline{(A\cup\text{B})}\iff\cap{A}\cap\overline{B}$, $\overline{(A\cap\text{B})}\iff\overline{A}\cup\overline{B}$
- Bevis:
$$
\begin{align}
x\in\overline{(A\cup\text{B})}\Rightarrow\text{x}\not\in\text{A}\cup\text{B}\Rightarrow
\left\{
\begin{aligned}
& \text{x}\notin\text{A} \\
& \text{x}\notin\text{B}
\end{aligned}
\right.
\Rightarrow\text{x}\notin\overline{A}\cap\overline{B}\Rightarrow
\left\{
\begin{aligned}
& \text{x}\in\overline{A} \\
& \text{x}\in\overline{B}
\end{aligned}
\right.
\Rightarrow
x\in\overline{(A\cup\text{B})}\text{. Vissar att }\overline{}
\end{align}
$$

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- Kartesisk produkt:
- $A\cdot\text{X} \overset{\mathrm{def}}{=} \{(a,b): a \in A, b \in B\}$,
-