sep-2-16_00

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2025-09-02 16:01:37 +02:00
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U = {x € Z+ : x <= 10}, A = {x : x udda, x != 5}, B = {x : x primtal}.
Bestäm |A|, |B|, ¨A, ¨B, AuB, A↓uB, och A\B
A = {1, 3, 7, 9}
B = {2, 3, 5, 7}
|A| = 4
|B| = 4
¨A = {2, 4, 5, 6, 8, 10}
¨B = {1, 4, 6, 8, 9, 10}
AuB = {1, 2, 3, 5, 7, 9}
A↓uB = {3, 7}
A\B = {1, 9}
A"delt"B = {1, 2, 5, 9}

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Mändoperation:
- Differens: A\B = {x € U | x € A och x !€ B}
- Symetrisk Differens A "delt" B = {x € U | x € AuB och x !€ A↓uB}
- A\B != B\A
Mänder 2:
Räkne regler:
- Dublekomplement: ¨¨A = A
- Idempotens: AuA = A, A↓uA = A
- Identitet: Auø = A, A↓uU = A
- Dominans: AuU = U, A↓uø = ø
- Kommutativ: AuB <=> BuA, A↓uB <=> B↓uA
- Associativ: (AuB)uC <=> Au(BuC), (A↓uB)↓uC <=> A↓u(B↓uC)
- Paranteser: om alla oprationer är u (union) eller ↓u (snit) spelar årder inge roll
- Ex: AuBuC eller A↓uB↓uC är okej men inte AuB↓uC eftersom Au(B↓uC) != (AuB)↓uC
- De Morgans: ¨(AuB) <=> ¨A↓u¨B, ¨(A↓uB) <=> ¨Au¨B
- Bevis 1:
x € ¨(AuB) => x !€ AuB => {x !€ A, x !€ B => x !€ {x € ¨A, x € ¨B => x € ¨(AuB). Visar att ¨(AuB) …c A↓uB.
x € ¨A↓u¨B => {x € ¨A, x € ¨B => {x !€ A, x !€ B => x !€ AuB => x € ¨(AuB). Visar att ¨A↓uB …c ¨(AuB).
Resultat: ¨(AuB) = ¨Au¨B