sep-2-16_00
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exercise-sep-2.txt
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exercise-sep-2.txt
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U = {x € Z+ : x <= 10}, A = {x : x udda, x != 5}, B = {x : x primtal}.
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Bestäm |A|, |B|, ¨A, ¨B, AuB, A↓uB, och A\B
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A = {1, 3, 7, 9}
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B = {2, 3, 5, 7}
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|A| = 4
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|B| = 4
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¨A = {2, 4, 5, 6, 8, 10}
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¨B = {1, 4, 6, 8, 9, 10}
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AuB = {1, 2, 3, 5, 7, 9}
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A↓uB = {3, 7}
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A\B = {1, 9}
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A"delt"B = {1, 2, 5, 9}
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notes-sep-2.txt
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notes-sep-2.txt
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Mändoperation:
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- Differens: A\B = {x € U | x € A och x !€ B}
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- Symetrisk Differens A "delt" B = {x € U | x € AuB och x !€ A↓uB}
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- A\B != B\A
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Mänder 2:
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Räkne regler:
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- Dublekomplement: ¨¨A = A
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- Idempotens: AuA = A, A↓uA = A
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- Identitet: Auø = A, A↓uU = A
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- Dominans: AuU = U, A↓uø = ø
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- Kommutativ: AuB <=> BuA, A↓uB <=> B↓uA
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- Associativ: (AuB)uC <=> Au(BuC), (A↓uB)↓uC <=> A↓u(B↓uC)
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- Paranteser: om alla oprationer är u (union) eller ↓u (snit) spelar årder inge roll
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- Ex: AuBuC eller A↓uB↓uC är okej men inte AuB↓uC eftersom Au(B↓uC) != (AuB)↓uC
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- De Morgans: ¨(AuB) <=> ¨A↓u¨B, ¨(A↓uB) <=> ¨Au¨B
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- Bevis 1:
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x € ¨(AuB) => x !€ AuB => {x !€ A, x !€ B => x !€ {x € ¨A, x € ¨B => x € ¨(AuB). Visar att ¨(AuB) …c A↓uB.
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x € ¨A↓u¨B => {x € ¨A, x € ¨B => {x !€ A, x !€ B => x !€ AuB => x € ¨(AuB). Visar att ¨A↓uB …c ¨(AuB).
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Resultat: ¨(AuB) = ¨Au¨B
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